We know that the intensity of the light on the screen is the Fourier transform of the intensity of the light coming through the slits, which, for several slits right next to each other (one big slit), is a top-hat function. The Fourier transform of a top-hat function is a sinc function, or decaying sine function, as shown above. The only difference is that the intensity of light on the screen is the square of the light wave hitting the screen, so the actual sinc function includes negative values. In addition, if the width of the top-hat is W, then in the Fourier transform, the sinc function equals zero at the points 1/W, 2/W, 3/W, and so on.
The width is also related to the wavelength of the light coming through the large slit, since there will be destructive interference where the light from the bottom of the slit and the light from the top of the slit are out of phase by λ/2. Therefore, the width of the center peak of intensity will be:
This is the angular resolution, and it simplifies to:
Therefore, the angular resolution of CCAT, which is a 25-meter telescope that detects wavelengths of 850 microns = 8.5 * 10-4 m, will have an angular resolution of:
where the angular resolution is measured in radians. The Keck 10-meter telescope observes in the J-band, which is defined as wavelengths between 1.1 and 1.4 micrometers = 1.1 * 10-6 to 1.4 * 10-6 m. Its angular resolution, using the maximum observation wavelength, is:
with D in radians, again. A smaller angular resolution means smaller sources can be resolved, since anything with an angular size larger than the angular resolution can be resolved by the telescope. This means that the Keck telescope, despite being smaller than CCAT, can resolve smaller objects in its observational range.
Secondary author: Joanna Robaszewski
Nice explanation! In the future, I'd suggest converting angles to arcseconds or arcminutes. These units are easier to understand since most astronomers will know the size of the object they want to observe in units of arcminutes or arcseconds (or degrees if it's very very big). It is generally true though that you have to work with radians for math purposes, and then convert to arcseconds at the very end.
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